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		<title>1.6a Lösning 12b - Versionshistorik</title>
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		<updated>2026-11-05T10:40:55Z</updated>
		<subtitle>Versionshistorik för denna sida på wikin</subtitle>
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	<entry>
		<id>https://wiki.mattekollen.se/index.php?title=1.6a_L%C3%B6sning_12b&amp;diff=15403&amp;oldid=prev</id>
		<title>Taifun den 29 september 2014 kl. 11.45</title>
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				<updated>2014-09-29T11:45:25Z</updated>
		
		<summary type="html">&lt;p&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Ny sida&lt;/b&gt;&lt;/p&gt;&lt;div&gt;::&amp;lt;math&amp;gt;\begin{array}{rcl}  \left|\,{5 \over x} + x\,\right| &amp;amp; &amp;lt; &amp;amp; 6  \\&lt;br /&gt;
                \left|\,{5 \over x} + {x^2 \over x}\,\right| &amp;amp; &amp;lt; &amp;amp; 6  \\&lt;br /&gt;
                         \left|\,{5 + x^2 \over x} \,\right| &amp;amp; &amp;lt; &amp;amp; 6  \\&lt;br /&gt;
                                      {|5 + x^2| \over |x|}  &amp;amp; &amp;lt; &amp;amp; 6               &amp;amp; | \;\; \cdot |x| \\&lt;br /&gt;
                                                  |5 + x^2|  &amp;amp; &amp;lt; &amp;amp; 6\,|x|  \qquad  &amp;amp; : \;   {\rm VL } \; |5 + x^2| &amp;gt; 0   \\&lt;br /&gt;
                                                    5 + x^2  &amp;amp; &amp;lt; &amp;amp; 6\,|x|          &amp;amp; | \;\; - 6\,|x|  \\&lt;br /&gt;
                                            x^2 - 6\,|x| + 5 &amp;amp; &amp;lt; &amp;amp; 0               &amp;amp; | \;\; + 4 \quad {\rm (Kvadratkomplettering)}  \\&lt;br /&gt;
                                            x^2 - 6\,|x| + 9 &amp;amp; &amp;lt; &amp;amp; 4               &amp;amp;                  \\&lt;br /&gt;
                                           (\,|x|\,-\,3\,)^2 &amp;amp; &amp;lt; &amp;amp; 4               &amp;amp; | \;\; \sqrt{{\color{White} x}}     \\&lt;br /&gt;
                                           |\,|x|\,-\,3\,|   &amp;amp; &amp;lt; &amp;amp; 2               &amp;amp; : \;\; \sqrt{{\color{White} x}} &amp;gt; 0 \\&lt;br /&gt;
                             -2 \quad &amp;lt; \quad |x|\,-\,3\,    &amp;amp; &amp;lt; &amp;amp; 2               &amp;amp; | \;\; + 3       \\&lt;br /&gt;
                                        1 \;\; &amp;lt; \;\; |x|    &amp;amp; &amp;lt; &amp;amp; 5               \\&lt;br /&gt;
       \end{array}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt; \begin{array}{lrcccl} \underline{x \; &amp;gt; \; 0 {\rm :}} &amp;amp; 1  &amp;amp; &amp;lt; &amp;amp;  x &amp;amp; &amp;lt; &amp;amp; 5                                    \\&lt;br /&gt;
                              \underline{x \; &amp;lt; \; 0 {\rm :}} &amp;amp; 1  &amp;amp; &amp;lt; &amp;amp; -x &amp;amp; &amp;lt; &amp;amp; 5   \qquad\qquad   | \;\; \cdot (-1) \\&lt;br /&gt;
                                                              &amp;amp; -1 &amp;amp; &amp;gt; &amp;amp;  x &amp;amp; &amp;gt; &amp;amp; -5                                   \\&lt;br /&gt;
                                                              &amp;amp; -5 &amp;amp; &amp;lt; &amp;amp;  x &amp;amp; &amp;lt; &amp;amp; -1&lt;br /&gt;
\end{array}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;u&amp;gt;Svar:&amp;lt;/u&amp;gt;&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt; -5 &amp;lt; x &amp;lt; -1 \qquad {\rm och} \qquad 1 &amp;lt; x &amp;lt; 5 &amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Taifun</name></author>	</entry>

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