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		<title>1.7 Lösning 3c - Versionshistorik</title>
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		<updated>2026-11-05T22:34:38Z</updated>
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	<entry>
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		<title>Taifun den 16 mars 2011 kl. 22.03</title>
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				<updated>2011-03-16T22:03:42Z</updated>
		
		<summary type="html">&lt;p&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Ny sida&lt;/b&gt;&lt;/p&gt;&lt;div&gt;:::&amp;lt;math&amp;gt;\begin{align}   4^x + 4^{x+1} &amp;amp; = 85                 \\&lt;br /&gt;
                     4^x + 4^x \cdot 4^1 &amp;amp; = 85                 \\&lt;br /&gt;
                         4^x \cdot (1+4) &amp;amp; = 85                 \\&lt;br /&gt;
                             4^x \cdot 5 &amp;amp; = 85      \qquad &amp;amp; &amp;amp;\,| \; / 5 \\&lt;br /&gt;
                                    4 ^x &amp;amp; = 17      \qquad &amp;amp; &amp;amp;\,| \;   \lg\,(\;\;)   \\&lt;br /&gt;
                              \lg\,(4^x) &amp;amp; = \lg\,17 \qquad &amp;amp; &amp;amp;: \;\text{3:e logaritmlag på VL} \\&lt;br /&gt;
                          x \cdot \lg\,4 &amp;amp; = \lg\,17 \qquad  &amp;amp; &amp;amp;\,| \; / \lg\,4                  \\&lt;br /&gt;
                                       x &amp;amp; = {\lg\,17 \over \lg\,4}                              \\&lt;br /&gt;
                                       x &amp;amp; = 2,043731&lt;br /&gt;
       \end{align}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Exakt lösning:&lt;br /&gt;
&lt;br /&gt;
::::::&amp;lt;math&amp;gt; x = {\lg\,17 \over \lg\,4} &amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Taifun</name></author>	</entry>

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