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		<id>https://wiki.mattekollen.se/index.php?action=history&amp;feed=atom&amp;title=2.3_L%C3%B6sning_5b</id>
		<title>2.3 Lösning 5b - Versionshistorik</title>
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		<updated>2026-11-05T10:39:48Z</updated>
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	<entry>
		<id>https://wiki.mattekollen.se/index.php?title=2.3_L%C3%B6sning_5b&amp;diff=15890&amp;oldid=prev</id>
		<title>Taifun den 10 oktober 2014 kl. 10.19</title>
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				<updated>2014-10-10T10:19:58Z</updated>
		
		<summary type="html">&lt;p&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Ny sida&lt;/b&gt;&lt;/p&gt;&lt;div&gt;:&amp;lt;math&amp;gt; y \, = \, 4\,x^2 - 380\,x + 9\,000 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt; y\,' = \, 8\,x - 380 &amp;lt;/math&amp;gt;&lt;br /&gt;
där &amp;lt;math&amp;gt; y\,' &amp;lt;/math&amp;gt; är utströmningsfunktionens derivata från [[2.4_Derivatans_definition#Exempel_Oljetank_.28utvidgat.29|&amp;lt;strong&amp;gt;&amp;lt;span style=&amp;quot;color:blue&amp;quot;&amp;gt;Exempel Oljetank (utvidgat)&amp;lt;/span&amp;gt;&amp;lt;/strong&amp;gt;]].&lt;br /&gt;
&lt;br /&gt;
Vi sätter derivatan till &amp;lt;math&amp;gt; -\,300 &amp;lt;/math&amp;gt; och beräknar &amp;lt;math&amp;gt; \,x &amp;lt;/math&amp;gt;:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\begin{array}{rcl} y\,' &amp;amp; = &amp;amp; 8\,x - 380  \\&lt;br /&gt;
                        -\,300 &amp;amp; = &amp;amp; 8\,x - 380  \\&lt;br /&gt;
                  -\,300 + 380 &amp;amp; = &amp;amp; 8\,x        \\&lt;br /&gt;
                            80 &amp;amp; = &amp;amp; 8\,x        \\&lt;br /&gt;
                            10 &amp;amp; = &amp;amp; x           \\&lt;br /&gt;
                             x &amp;amp; = &amp;amp; 10&lt;br /&gt;
       \end{array}&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Taifun</name></author>	</entry>

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