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		<title>3.2 Lösning 1b - Versionshistorik</title>
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		<updated>2026-11-05T05:31:19Z</updated>
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		<title>Taifun den 8 december 2014 kl. 15.11</title>
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				<updated>2014-12-08T15:11:47Z</updated>
		
		<summary type="html">&lt;p&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Ny sida&lt;/b&gt;&lt;/p&gt;&lt;div&gt;Vi har:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt; y = f(x) = - 9\,x^2 + 6\,x + 10 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
För att få maximala höjden sätter vi in maximipunkten &amp;lt;math&amp;gt; \displaystyle x = {1 \over 3} &amp;lt;/math&amp;gt; från a) i &amp;lt;math&amp;gt; \, f(x) \, &amp;lt;/math&amp;gt;:&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt; y = f\left({1 \over 3}\right) = - 9\cdot \left({1 \over 3}\right)^2 + 6\cdot {1 \over 3} + 10 = - 9\cdot \left({1 \over 9}\right) + {6 \over 3} + 10 = - {9 \over 9} + 2 + 10 = 11 &amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Taifun</name></author>	</entry>

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