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		<title>3.5 Lösning 3a - Versionshistorik</title>
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		<updated>2026-11-04T23:10:04Z</updated>
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	<entry>
		<id>https://wiki.mattekollen.se/index.php?title=3.5_L%C3%B6sning_3a&amp;diff=21231&amp;oldid=prev</id>
		<title>Taifun den 1 februari 2015 kl. 14.36</title>
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				<updated>2015-02-01T14:36:08Z</updated>
		
		<summary type="html">&lt;p&gt;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Ny sida&lt;/b&gt;&lt;/p&gt;&lt;div&gt;Rektangelns are är &amp;lt;math&amp;gt; \; A \; = \; x \, \cdot \, y \, &amp;lt;/math&amp;gt;. Den är given med &amp;lt;math&amp;gt; \, 25 \, &amp;lt;/math&amp;gt; i uppgiften &amp;lt;math&amp;gt; \quad \Longrightarrow \quad x \, \cdot \, y \, = \, 25 \, &amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
Vi löser ut &amp;lt;math&amp;gt; \, y \, &amp;lt;/math&amp;gt; ur detta samband:&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt;\begin{array}{rcl}  x \, \cdot \, y &amp;amp; = &amp;amp; 25  \\&lt;br /&gt;
                                          y &amp;amp; = &amp;amp; {25 \over x}&lt;br /&gt;
      \end{array}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Problemets bivillkor är&amp;lt;span style=&amp;quot;color:black&amp;quot;&amp;gt;:&amp;lt;/span&amp;gt;&lt;br /&gt;
&lt;br /&gt;
::&amp;lt;math&amp;gt; y \, = \, {25 \over x} &amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Taifun</name></author>	</entry>

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